Crease of a square paper
A square sheet of paper ABCD is so
folded that B falls on the mid-point of M of CD. Prove that the crease
will divide BC in the ratio 5:3.
Discussion:
Assuming
the side of the square is ‘s’. Let a part of the crease be ‘x’ (hence
the remaining part is ‘s-x’). We apply Pythagoras Theorem we solve for
x:
implies
and 
Hence the ratio is 5:3.
Standard
Discussion:
Hence the ratio is 5:3.









